The area of the region enclosed between the curves y = x 2 2x 2 and x 2 6 is equal to 9 Example 2 Find the area of the region enclosed between the curves defined by the equations y = √(x 2) , y = x and y = 0 Solution to Example 2 We first graph all three curves and examine the region enclosedY'\frac {4} {x}y=x^3y^2, y (2)=1 laplace\y^ {\prime}2y=12\sin (2t),y (0)=5 bernoulli\\frac {dr} {dθ}=\frac {r^2} {θ} ordinarydifferentialequationcalculator xy'y=x^ {2}2x1 en Sign In Sign in with Office365 Sign in with FacebookGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Y=x-2/x^2+2x-8-Show all of your steps y=x^22x y=3x Algebra Solve the system of equations using substitution x 4y = 5 3x 8y = 45 When I tried to solve it, I got x=17 and y=3 When I plugged these into the first equation, it didn't work out at all Could someone please show me the College algebraX^45x^24=0 \sqrt{x1}x=7 \left3x1\right=4 \log _2(x1)=\log _3(27) 3^x=9^{x5} equationcalculator y=2x^{2}5x3 en Related Symbolab blog posts High School Math Solutions – Quadratic Equations Calculator, Part 1 A quadratic equation is a second degree polynomial having the general form ax^2 bx c = 0, where a, b, and
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Knowledgebase, relied on by millions of students &Precalculus Find the Center and Radius x^22xy^2=0 x2 − 2x y2 = 0 x 2 2 x y 2 = 0 Complete the square for x2 −2x x 2 2 x Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = − 2, c = 0 a = 1, b = 2, c = 0 Consider the vertex form of a parabolaTranscribed image text = Homework 33 Homework Differentiate Find y' for y= x2 2 2x 2x2 4x O A y' = (2 2x)2 2x3 4x2 4x O B y' = (22x)2 2x O C y' = (2 2x)2 6x2 4x OD y' = (22x)
X^ {2}2x=y4 Subtract 4 from both sides x^ {2}2x1^ {2}=y41^ {2} Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square x^ {2}2x1=y41Sketch the region enclosed by the curves y2 = 2x6 and y = x−1 and find the area Sketch the region enclosed by the curves y2 = 2x6 and y = x−1 and find the areaShow all of your steps y=x^22x **y=x^22x (2/2)^2=1 1=answer** y=3x **y=3x (3/2)^2=225 225=answer** am i right or wrong, if im wrong could someone show me the steps math question 1 Note Enter your answer and show all the steps that you use to solve this problem in the space provided Solve the inequality and describe the solution
Answer (1 of 6) That's a circle Compare x^2y^22x=0 with the general equation of a circle x^2y^22gx2fyc=0 and write down the values of the constants g, f and c g=1 f=0 c=0 The centre of the circle is (g,f)\equiv(1,0) The radius of the circle is \sqrt{g^2f^2c}=\sqrt{1} IfSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreWhat we are transforming is the basis of #y=x^2# where #x_(vertex)=0# Let the vertex of #y=x^2>(x_1,y_1)=(0,0)# Note this is the same as #y=x^x0# Note that the yintercept is at #x=0# So for this case the yintercept is #y=(0)^x0=0# #color(blue)(Transformation left or right Shift left or right)# Let the vertex of #y=x^22x >(x
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Is addition and one when it is subtraction x^ {2}2x5y=yy Subtract y from both sides of the equation x^ {2}2x5y=0How do you graph # y=x^22x2#?Since you can choose any value you like for x, pick something that will make the arithmetic simple 0 is always a good choice So our first point is (0,2), because we chose 0 for x, and that resulted in 2 for y Let's try x = 1 So the second point is (1,3), because we chose 1 for x, and that resulted in 3 for y Plot the points Then draw the line
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Find the Maximum/Minimum Value y=x^22x3 y = x2 − 2x − 3 y = x 2 2 x 3 The maximum or minimum of a quadratic function occurs at x = − b 2a x = b 2 a If a a is negative, the maximum value of the function is f (− b 2a) f ( b 2 a) If a a is positive, the minimum value of the function is f (− b 2a) f ( b 2 a)X3=5 1/3 1/4 y=x^21 Disclaimer This calculator is not perfect Please use at your own risk, and please alert us if something isn't working Thank youFactor 2x^2xyy^2 2x2 − xy − y2 2 x 2 x y y 2 For a polynomial of the form ax2 bx c a x 2 b x c, rewrite the middle term as a sum of two terms whose product is a⋅c = 2⋅−1 = −2 a ⋅ c = 2 ⋅ 1 = 2 and whose sum is b = −1 b = 1 Tap for more steps Reorder terms 2 x 2 − y 2 − x y 2 x 2 y 2 x y
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Notice the numerator and denominator have the same quadratic expression y 2 x 2 2 x y = (y x) 2 This suggests the substitution u = ( y x ) d y d x = ( ( y x ) 2 ( y x ) ( y x ) 2 2 ( y xConsider the curve given by y^2 = 2xy (a) show that dy/dx= y/(2yx) (b) Find all points (x,y) on the curve where the line tangent to the curve has slope 1/2 (c) Show that there are now points (x,y) on the curve where the line Calculus Find normals to the curve xy2xy=0 that are parallel to the line 2xy=0 I have the answer at(1,1), y=2x3, and at (3,3), y=2x3 How do we get this?2 hours agoThe domain for $x$ and $y$ are all integers $∃x∀y (y=x^22x1)$ can be interpreted as There is an $x$ for all $y$ such that it satisfies $y=x^22x1$ There is
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The factors are (xy)(xy) or (xy)^2 We need to factor the trinomial x^22xyy^2 The factors of x^2 = (x)(x) The factors of y^2 = (y)(y) Since the second sign is positive we are adding the factors meaning the signs of the factors need to be the same Since the first sign is negative both signs must be negativeWe can try to factor x 2 −2xy−y 2 but we must do some rearranging first Change signs y 2 2xy−x 2 = − 1 k 2 Replace − 1 k 2 by c y 2 2xy−x 2 = c Add 2x 2 to both sides y 2 2xyx 2 = 2x 2 c Factor (yx) 2 = 2x 2 c Square root yx = ±√(2x 2 c) Subtract x from both sides y = ±√(2x 2 c) − x And we have theProfessionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music
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Is addition and one when it is subtractionSubtract y from both sides Subtract y from both sides x^ {2}2x48y=0 x 2 2 x − 4 8 − y = 0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ±Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology &
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Simple and best practice solution for 2(xy)=2x2y equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itA solid is under {eq}z = x^2 y^2 {/eq} and inside {eq}x^2 = 2x y^2 {/eq} Write an iterated integral in polar coordinates to determine the volume of the solidAdd 2 2 to both sides of the equation x2 y2 2x−2y = 2 x 2 y 2 2 x 2 y = 2 Complete the square for x2 2x x 2 2 x Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = 2, c = 0 a = 1, b = 2
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4 x 2 − 2 x − 2 = 0 Divide both sides by 2 Divide both sides by 2 2x^ {2}x1=0 2 x 2 − x − 1 = 0 To solve the equation, factor the left hand side by grouping First, left hand side needs to be rewritten as 2x^ {2}axbx1 To find a and b, set up a system to be solvedY = x2 − 2x − 2 y = x 2 2 x 2 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 2 x − 2 x 2 2 x 2 Tap for more steps Use the form a x 2 b x c a x 2 b xThe quadratic formula gives two solutions, one when ±
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The answer is =2(1lnx)x^(2x) We need (uv)'=u'vuv' y=x^(2x) lny=ln(x^(2x)) lny=2xlnx Differentiating wrt x 1/ydy/dx=2(x*1/x1*lnx) dy/dx=2(1lnx)y dy/dx=2(1lnx)x^(2x)X^ {2}2x5=y All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ±Algebra Simplify 2x^2x^2 2x2 − x2 2 x 2 x 2 Subtract x2 x 2 from 2x2 2 x 2 x2 x 2
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Functionvertexcalculator vértice y=x^{2}2x3 en Related Symbolab blog posts Functions A function basically relates an input to an output, there's an input, aWeekly Subscription $249 USD per week until cancelled Monthly Subscription $799 USD per month until cancelled Annual Subscription $3499 USD per year until cancelledRewrite as x^22xy=0 This is a quadratic equation in variable x Don't be confused, I'm just pointing out that we will temporarily be thinking of y as a constant (a number) We would solve by factoring if we could, but we can't so we'll use the quadratic formula, which says that the solutions to 2x^2 bx c = 0 are x=(bsqrt(b^24ac))/(2a)
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Professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music(2 pts) y = x2 4x – 3 y = x 1 I have tried everything before coming here, but I'm still stuck algebra Solve the system of equations algebraically Show all of your steps y=x^22x **y=x^22x (2/2)^2=1 1=answer** y=3x **y=3x (3/2)^2=225 225=answer** am i right or wrong, if im wrong could someone show me the stepsGraph the parent quadratic (y = x^2) by creating a table of values using select x values The graph of this parent quadratic is called a parabolaNOTE Any
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4dy^ {2}x^ {2}\left (3d\right)x4dy=0 4 d y 2 x 2 ( − 3 d) x 4 d y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 4y^ {2}d for a, 3d for b, and 4dy for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x c = 0Graph y=2xx^2 y = 2x − x2 y = 2 x x 2 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Reorder 2 x 2 x and − x 2 x 2 y = − x 2 2 x y = x 2 2 x Complete the square for − x 2 2 x x 2 2 xX^2 2 y^2 = 1 Natural Language;
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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology &Simplifying y = 2x * x 2 Multiply x * x 2 y = 2x 3 Solving y = 2x 3 Solving for variable 'y' Move all terms containing y to the left, all other terms to the right Simplifying y = 2x 3 You can always share this solution See similar equationsDerivative x^2(xy)^2 = x^2y^2 Natural Language;
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Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer SCooke Set up a column for x and y (the expression) Calculate y for each x, then plot the points on graph paper Explanation Generating the points to plot is a necessary first step, whether you do it by handThe line x = a is called a Vertical Asymptote of the curve y = f(x) if at least one of the following statements is true Method 2 For rational functions, vertical asymptotes are vertical lines that correspond to the zeroes points of the denominator
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